Math  /  Trigonometry

QuestionTrigonometry triangles ID: 20369739
In triangle ABCA B C, the measure of angle BB is 9090^{\circ} and BD\overline{B D} is an altitude of the triangle. The length of AB\overline{A B} is 15 and the length of AC\overline{A C} is 23 greater than the length of AB\overline{A B}. What is the value of BCBD\frac{B C}{B D} ? A. 1538\frac{15}{38} B. 1523\frac{15}{23} PDF de-sign PDF forms \& eements C. 2315\frac{23}{15} D. 3815\frac{38}{15} trial 5:15 PM Search 11/27/2024

Studdy Solution
Calculate BCBD\frac{BC}{BD}:
BCBD=121915121938 \frac{BC}{BD} = \frac{\sqrt{1219}}{\frac{15 \cdot \sqrt{1219}}{38}}
Simplify the expression:
BCBD=3815 \frac{BC}{BD} = \frac{38}{15}
The value of BCBD\frac{BC}{BD} is:
3815 \boxed{\frac{38}{15}}

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