Question Evaluate the definite integral of $\frac{4y}{e^{2y}}$ from 0 to 1.

Studdy Solution
The final answer is the negative of the sum of $e^{-2}$ and 1.
$$\int_{0}^{1} \frac{4 y}{e^{2 y}} d y = -e^{-2} - 1$$