Math  /  Algebra

Question Let A=(111101)\text { Let } A=\left(\begin{array}{ccc} 1 & -1 & -1 \\ -1 & 0 & 1 \end{array}\right)
The matrix transformation associated to AA is TA:R3R2T_{A}: \mathbb{R}^{3} \rightarrow \mathbb{R}^{2} defined by the formula TA([xyz])=[]T_{A}\left(\left[\begin{array}{l} x \\ y \\ z \end{array}\right]\right)=\left[\begin{array}{l} \square \\ \square \end{array}\right]
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Studdy Solution
So, the transformation TAT_A is defined by: TA([xyz])=[xyzx+z] T_A\left(\begin{bmatrix} x \\ y \\ z \end{bmatrix}\right) = \begin{bmatrix} x - y - z \\ -x + z \end{bmatrix}

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