Math  /  Algebra

QuestionIs the mapping f={(a,2),(b,5),(c,7),(d,5)}f=\{(\mathrm{a}, 2),(\mathrm{b}, 5),(\mathrm{c}, 7),(\mathrm{d}, 5)\} a function from A={a,b,c,d}A=\{\mathrm{a}, \mathrm{b}, \mathrm{c}, \mathrm{d}\}?

Studdy Solution
From steps4-7, we can see that every element in AA is paired with exactly one element in BB. Therefore, ff is a function from AA to BB.
The correct answer is Yes, because each element in the domain is paired with a unique element in the range.

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