Math  /  Algebra

Questionxxercise 06()06(* *)
Let EE be a set and f:EEf: E \rightarrow E such that fff=ff \circ f \circ f=f. Show that ff is injective if and only if gg is surjective.
Exercise 07()07(* *)

Studdy Solution
Ainsi, f(f(x))=x f(f(x)) = x pour tout xE x \in E , ce qui implique que f f est injective.
Nous avons montré que f f est injective si et seulement si f f est surjective.

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