Math  /  Calculus

QuestionFind the value of kk such that limx2f(x)=3\lim _{x \rightarrow 2} f(x)=3 for f(x)=(x2)(x2k2)(x24)(xk)f(x)=\frac{(x-2)(x^{2}-k^{2})}{(x^{2}-4)(x-k)}.

Studdy Solution
olving the equation for kk gives us3=2+k43 = \frac{2+k}{4}3×4=2+k3 \times4 =2 + k12=2+k12 =2 + kk=122k =12 -2k=10k =10So, the value of kk that makes limx2f(x)=3\lim{x \rightarrow2} f(x)=3 is 1010.
The correct answer is (C)10.

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