QuestionLet f(x) and g(x) be differentiable functions Evaluate f′(−3) for the function
f(x)=(x2+2x−3)(x3+1)g(2x+5)g(x+2).
(a) −132
(b) 213f(x)=g(2x+5)g(x+2)⋅(x−1)
(c) -1
(d) 0x+2=
(e) 1324−3
Studdy Solution Hesaplamaları yaparak sonucu bulun: f′(−3)=((−27+1)g(−1))2((−6+2)g(−1)+(9−6−3)g′(−1))(−27+1)g(−1)−(9−6−3)g(−1)(27g(−1)+(−27+1)g′(−1)⋅2) f′(−3)=((−26)g(−1))2(−4g(−1)+0)(−26)g(−1)−0 f′(−3)=676g(−1)2104g(−1)2 f′(−3)=676104=132
Sonuç: f′(−3)=132