Math  /  Algebra

QuestionLet f(x)=2x1f(x)=2 x-1
The smallest positive number for which f(cos(f(x)))=0f(\cos (f(x)))=0 is x=x= \square Hint: Begin by using the definition of ff to remove ff from the equation. Then solve a linear equation for cos(2x1)\cos (2 x-1). Then solve for xx.

Studdy Solution
The smallest positive number for which f(cos(f(x)))=0f(\cos(f(x))) = 0 is x=π6+12x = \frac{\pi}{6} + \frac{1}{2}.

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