QuestionLet $X$ be a random variable with a CDF equal to $F(x)=c \cdot\left(\frac{1}{1.5}-x e^{-x}\right) \cdot \mathbb{1}_{[1.8 ; \infty)}(x)$, where $c$ is a constant. Find $c$ :
Answer: 3.361 $\square$
The correct answer is: 1.500
For the random variable defined aboveP $(X \in[3.96 ; \infty))$ amounts to
Answer: $\square$ 1