Math  /  Calculus

Questionlimx10x2πx+π\lim_{{x \to 10}} \frac{x^2 - \pi}{x + \pi}

Studdy Solution
Simplify the expression:
102π10+π=100π10+π \frac{10^2 - \pi}{10 + \pi} = \frac{100 - \pi}{10 + \pi}
Solution: Therefore, the limit is:
limx10x2πx+π=100π10+π \lim_{{x \to 10}} \frac{x^2 - \pi}{x + \pi} = \frac{100 - \pi}{10 + \pi}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord