QuestionFind the limit: $\lim _{x \rightarrow 0} \frac{1-\cos x}{3 \sin ^{2} x}$.

Studdy Solution
We know that $\cos0 =1$, so we substitute this value into the function.
$$\frac{1}{6 \cos0} = \frac{1}{6}$$So, the limit of the function $\frac{1-\cos x}{3 \sin ^{2} x}$ as $x$ approaches $0$ is $\frac{1}{6}$.