QuestionFind the limit: $\lim _{x \rightarrow 0} \frac{(3+x)^{2}-9}{x}$.

Studdy Solution
Finally, we substitute $x =0$ into the simplified expression to find the limit.
$$\lim{x \rightarrow0} (6 + x) =6 +0 =6$$The limit of the function $\frac{(3+x)^{2}-9}{x}$ as $x$ approaches $0$ is $6$.