Math / CalculusQuestionFind the limit: limx→π3sin2xsinx\lim _{x \rightarrow \frac{\pi}{3}} \frac{\sin 2 x}{\sin x}limx→3πsinxsin2x.Studdy SolutionCalculate the final result.2×12=12 \times \frac{1}{2} =12×21=1So, limx→π3sin2xsinx=1\lim{x \rightarrow \frac{\pi}{3}} \frac{\sin2 x}{\sin x} =1limx→3πsinxsin2x=1. View Full Solution - FreeWas this helpful?
