QuestionFind the limit: $\lim _{x \rightarrow+\infty} \sin ^{-1}\left(\frac{x}{1-2 x}\right)$.

Studdy Solution
The inverse sine of $-\frac{1}{2}$ is $-\frac{\pi}{6}$, so the limit is$$-\frac{\pi}{6}$$The limit as $x$ approaches positive infinity of $\sin^{-1}\left(\frac{x}{1-2x}\right)$ is $-\frac{\pi}{6}$.