Math  /  Geometry

QuestionBDundefined\overrightarrow{\mathrm{BD}} bisects ABC\angle A B C. If mABD=(3x+15)m \angle A B D=(3 x+15)^{\circ} and mDBC=(5x12)m \angle D B C=(5 x-12)^{\circ}, find mABCm \angle A B C.

Studdy Solution
Calculate the value of mABCm \angle A B CmABC=55.5+55.5=111m \angle A B C =55.5^{\circ} +55.5^{\circ} =111^{\circ}So, mABC=111m \angle A B C =111^{\circ}.

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