Math  /  Geometry

Questionlint. (iii) The point (points) are of the form (k,2k)(k, 2 k). ind the point on the xx-axis which is equidistant from the points (2,5)(2,-5) and (2,9)(-2,9).

Studdy Solution
Simplify and solve for x x :
x24x+29=x2+4x+85 x^2 - 4x + 29 = x^2 + 4x + 85
Cancel x2 x^2 from both sides:
4x+29=4x+85 -4x + 29 = 4x + 85
Combine like terms:
4x4x=8529 -4x - 4x = 85 - 29
8x=56 -8x = 56
Divide by 8-8:
x=7 x = -7
The point on the x x -axis is:
(7,0) \boxed{(-7, 0)}

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