Questionما قيبة $$\lim _{x \rightarrow-3} \frac{x^{3}+27}{x^{2}+4 x+3}=$$
اخترأحد الذيارات $\frac{2}{27}$ $\frac{-27}{2}$ $\frac{27}{2}$ $\frac{-2}{27}$

Studdy Solution
Substitute $x = -3$ into the simplified expression:
$$\frac{(-3)^2 - 3(-3) + 9}{-3 + 1} = \frac{9 + 9 + 9}{-2} = \frac{27}{-2}$$
The value of the limit is:
$$\boxed{\frac{-27}{2}}$$