Math  /  Algebra

QuestionMaximize p=5x4y+3zp=5 x-4 y+3 z subject to 2x+2z1005y5z502x5y50x0,y0,z0\begin{array}{c} 2 x+2 z \leq 100 \\ 5 y-5 z \leq 50 \\ 2 x-5 y \leq 50 \\ x \geq 0, y \geq 0, z \geq 0 \end{array}

Studdy Solution
After evaluating the objective function at all vertices, the maximum value of pp is found to be **pmaxp_{\text{max}}** at the vertex (x,y,z)(x, y, z).

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