Math  /  Word Problems

QuestionMrs. Bennett swims 50 feet in 12.3 seconds. What is her speed in MPH?

Studdy Solution
Assumptions1. Mrs. Bennett swims a distance of50 feet in12.3 seconds. We need to convert this speed to miles per hour (MPH)
, we need to convert the distance from feet to miles. There are5280 feet in a mile.
Distanceinmiles=Distanceinfeet/5280Distance\, in\, miles = Distance\, in\, feet /52803Now, plug in the given value for the distance in feet to calculate the distance in miles.
Distanceinmiles=50/5280Distance\, in\, miles =50 /52804Calculate the distance in miles.
Distanceinmiles=50/52800.00947milesDistance\, in\, miles =50 /5280 \approx0.00947\, miles5Next, we need to convert the time from seconds to hours. There are3600 seconds in an hour.
Timeinhours=Timeinseconds/3600Time\, in\, hours = Time\, in\, seconds /36006Now, plug in the given value for the time in seconds to calculate the time in hours.
Timeinhours=12.3/3600Time\, in\, hours =12.3 /36007Calculate the time in hours.
Timeinhours=12.3/36000.00342hoursTime\, in\, hours =12.3 /3600 \approx0.00342\, hours8Now that we have both the distance in miles and the time in hours, we can calculate the speed in MPH. Speed is calculated by dividing the distance by the time.
SpeedinMPH=Distanceinmiles/TimeinhoursSpeed\, in\, MPH = Distance\, in\, miles / Time\, in\, hours9Plug in the values for the distance in miles and the time in hours to calculate the speed in MPH.
SpeedinMPH=0.00947/0.00342Speed\, in\, MPH =0.00947 /0.0034210Calculate the speed in MPH.
SpeedinMPH=0.00947/0.00342.77MPHSpeed\, in\, MPH =0.00947 /0.00342 \approx.77\, MPHMrs. Bennett is swimming at a speed of approximately.77 MPH.

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