Math  /  Data & Statistics

QuestionMultiple-choice questions each have four possible answers ( a,b,c,da, b, c, d ), one of which is correct Assume that you guess the answers to three such questions. a. Use the multiplication rule to find P(WCC)\mathrm{P}(\mathrm{WCC}), where C denotes a correct answer and W denotes a wrong answer. P(WCC)=364 (Type an exact answer.) P(W C C)=\frac{3}{64} \text { (Type an exact answer.) } b. Beginning with WCC, make a complete list of the different possible arrangements of two correct answers and one wrong answer, then find the probability for each entry in the list. P(WCC) see above P(CCW)=364P(CWC)=364\begin{array}{l} P(W C C)-\text { see above } \\ P(C C W)=\frac{3}{64} \\ P(C W C)=\frac{3}{64} \end{array} (Type exact answers.) c. Based on the preceding results, what is the probability of getting exactly two correct answers when three guesses are made? \square (Type an exact answer.)

Studdy Solution
Sum the probabilities to find the total probability of getting exactly two correct answers:
P(exactly two correct)=P(WCC)+P(CCW)+P(CWC) P(\text{exactly two correct}) = P(WCC) + P(CCW) + P(CWC)
P(exactly two correct)=364+364+364 P(\text{exactly two correct}) = \frac{3}{64} + \frac{3}{64} + \frac{3}{64}
P(exactly two correct)=964 P(\text{exactly two correct}) = \frac{9}{64}
The probability of getting exactly two correct answers when three guesses are made is:
964 \boxed{\frac{9}{64}}

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