QuestionMultiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits. $$\begin{array}{c} 933.55 \mathrm{~g} \div 0.33 \mathrm{~mL}=\square \frac{\mathrm{g}}{\mathrm{mL}} \\ 653.45 \mathrm{~mol} \div 45.914 \mathrm{~L}=\square \frac{\mathrm{mol}}{\mathrm{L}} \\ 7.81 \frac{\mathrm{g}}{\mathrm{mL}} \times 1.525 \mathrm{~mL}=\square \mathrm{g} \end{array}$$ $\square$ $$\times 10$$

Studdy Solution
Perform the multiplication and round the result to the correct number of significant digits.
$$7.81 \frac{\mathrm{g}}{\mathrm{mL}} \times 1.525 \mathrm{~mL} = 11.90025 \mathrm{~g}$$
Since the measurement with the fewest significant digits is $7.81 \frac{\mathrm{g}}{\mathrm{mL}}$ with 3 significant digits, we round the result to 3 significant digits:
$$11.90025 \approx 11.9 \mathrm{~g}$$
Solution:
1. $$\frac{933.55 \mathrm{~g}}{0.33 \mathrm{~mL}} = 2800 \frac{\mathrm{g}}{\mathrm{mL}}$$
2. $$\frac{653.45 \mathrm{~mol}}{45.914 \mathrm{~L}} = 14.224 \frac{\mathrm{mol}}{\mathrm{L}}$$
3. $$7.81 \frac{\mathrm{g}}{\mathrm{mL}} \times 1.525 \mathrm{~mL} = 11.9 \mathrm{~g}$$