Math  /  Data & Statistics

QuestionPart 5 of 8 HW Score: 12.5%,112.5 \%, 1 of 8 points O Points: 0 of 1
Assume that the differences for the given data are normally distributed. Complete parts (a) through (d). Click here to view the sample data. Click here to view the table of critical t-values. Points: 0 of 1 \qquad (a) Determine di=XiYid_{i}=X_{i}-Y_{i} for each pair of data. \begin{tabular}{|l|c|c|c|c|c|c|c|} \hline Observation & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\ \hline di\mathbf{d}_{\mathbf{i}} & -0.5 & 1.1 & -3.3 & -3.8 & 0.5 & -2.3 & -2.9 \\ \hline \end{tabular} (b) Compute d\overline{\mathrm{d}} and sd\mathrm{s}_{\mathrm{d}}. d=1.600\overline{\mathrm{d}}=-1.600 (Round to three decimal places as needed.) sd=1.950\mathrm{s}_{\mathrm{d}}=1.950 (Round to three decimal places as needed.) (c) Test if μd<0\mu_{d}<0 at the α=0.05\alpha=0.05 level of significance.
Determine the null and alternative hypotheses. Choose the correct answer. A. H0:μd=0H_{0}: \mu_{d}=0 H1:μd<0\mathrm{H}_{1}: \mu_{\mathrm{d}}<0 B. H0:μd<0H_{0}: \mu_{d}<0 H1:μd=0H_{1}: \mu_{d}=0 C. H0:μd>0H_{0}: \mu_{d}>0 H1:μd<0\mathrm{H}_{1}: \mu_{d}<0 D. H0:μd<0H_{0}: \mu_{d}<0 H1:μd>0H_{1}: \mu_{d}>0 Determine the test statistic. The test statistic is \square (Round to two decimal places as needed.)

Studdy Solution
The test statistic is approximately **-2.17**.
Since this is less than our critical value, we reject the null hypothesis.
This means there's *significant* evidence to suggest that the average difference is less than zero!

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