Math  /  Algebra

Questionpoints Points: 0 of 1
For the equation, (a) solve for xx in terms of yy, and (b) solve for yy in terms of xx. 8x2+2xy+5y2=88 x^{2}+2 x y+5 y^{2}=8 (a) Solve for xx in terms of yy. x=x=\square (Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expressi. comma to separate answers as needed.)

Studdy Solution
(a) x=y±6439y28x = \frac{-y \pm \sqrt{64 - 39y^2}}{8} (b) y=x±4039x25y = \frac{-x \pm \sqrt{40 - 39x^2}}{5}

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