Math  /  Data & Statistics

QuestionProblem 3: Using the tabular data, determine the order of the reaction and the reaction rate. Graph the data to support your answer. The reaction is peroxide to water and oxygen as shown in stoichiometric equilibrium as below. 2H2O22H2O+O22 \mathrm{H}_{2} \mathrm{O}_{2} \Leftrightarrow 2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}
The initial concentration of the hydrogen peroxide is 1.0 M and decreases according to the collected data shown in the table: \begin{tabular}{|c|c|} \hline Time (s)(\mathbf{s}) & {[H2O2](M)\left[\mathrm{H}_{2} \mathrm{O}_{2}\right] \mathbf{( M )}} \\ \hline 0 & 1.0 \\ \hline 10 & 0.8 \\ \hline 20 & 0.6 \\ \hline 30 & 0.4 \\ \hline 40 & 0.2 \\ \hline \end{tabular}
This dataset shows how the concentration of hydrogen peroxide decreases linearly over time in a zero-order reaction. If you have any questions or need further details, feel free to ask!

Studdy Solution
The reaction is **zero-order**, and the rate constant is 0.02 M/s\text{0.02 M/s}.
The rate law is simply Rate=0.02 M/s\text{Rate} = \text{0.02 M/s}.

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