Question$P(x)=3 x^{4}-16 x^{3}+21 x^{2}+4 x-12 \quad, x_{1}=-2 / 3$

Studdy Solution
Collect all roots of the polynomial $P(x)$.
The roots are $x_1 = -2/3$, $x_2 = 1$, $x_3 = 3$, and $x_4 = 2$.
Solution: The roots of the polynomial $P(x) = 3x^4 - 16x^3 + 21x^2 + 4x - 12$ are:
$x = -\frac{2}{3}, \quad x = 1, \quad x = 3, \quad x = 2$