Math

QuestionQ15: For XB(n,p)X \sim B(n, p) we have Var(X)=0.8E(X)\operatorname{Var}(X)=0.8 E(X). Find pp

Studdy Solution
Solve the equation for p p :
First, divide both sides by np np (assuming np0 np \neq 0 ):
1p=0.81 - p = 0.8
Subtract 0.8 from both sides:
10.8=p1 - 0.8 = p
p=0.2p = 0.2
The value of p p is:
0.2\boxed{0.2}

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