Math  /  Geometry

QuestionQ2: A)Find the equation of the hyperbola whose center is at the origin and one of its foci is the focus of the parabola whose equation is y2+16x=0y^{2}+16 x=0 and hyperbola passes through at the point (6,22)(6,2 \sqrt{2})

Studdy Solution
كتابة معادلة القطع الزائد:
المعادلة هي:
x29y27=1 \frac{x^2}{9} - \frac{y^2}{7} = 1
المعادلة النهائية للقطع الزائد هي:
x29y27=1 \boxed{\frac{x^2}{9} - \frac{y^2}{7} = 1}

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