Math  /  Calculus

QuestionQuestion 5 (15 points) a. On pose le probleme d'optimisation suivant: minx,yx2+y2 t.q. x+py=1,p0\min _{x, y} x^{2}+y^{2} \text { t.q. } x+p y=1, \quad p \neq 0
Formez le Lagrangien et trouvez le point stationnaire. Est-ce que les conditions du second ordre sont satisfaites? Calculez le minimum mm^{*} atteint.

Studdy Solution
Calculer le minimum mm^* atteint en substituant xx et yy dans la fonction objectif:
m=x2+y2=(11+p2)2+(p1+p2)2 m^* = x^2 + y^2 = \left(\frac{1}{1 + p^2}\right)^2 + \left(\frac{p}{1 + p^2}\right)^2
m=1(1+p2)2+p2(1+p2)2 m^* = \frac{1}{(1 + p^2)^2} + \frac{p^2}{(1 + p^2)^2}
m=1+p2(1+p2)2 m^* = \frac{1 + p^2}{(1 + p^2)^2}
m=11+p2 m^* = \frac{1}{1 + p^2}
La valeur minimale atteinte est:
m=11+p2 m^* = \frac{1}{1 + p^2}

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