Math  /  Calculus

QuestionQuestion
Evaluate 02(7f(x)6g(x))dx\int_{0}^{2}(7 f(x)-6 g(x)) d x given that 014f(x)dx=9,02f(x)dx=9,014g(x)dx=5\int_{0}^{14} f(x) d x=9, \int_{0}^{2} f(x) d x=-9, \int_{0}^{14} g(x) d x=5, and 02g(x)dx=3\int_{0}^{2} g(x) d x=3
Provide your answer below:

Studdy Solution
Calculate the result:
=6318= -63 - 18 =81= -81
The value of the integral is:
81\boxed{-81}

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