Math / Geometry

QuestionРеши задачу. Дана прямоугольная трапеция $MNKL$ с основаниями $ML = 260$ мм и $NK = 208$ мм. Найди её площадь, если $\angle KLM = 45^\circ$ . Вырази ответ в дм $^{2}$ .

Studdy Solution
Площадь трапеции равна $\frac{234 \cdot 26 \cdot \sqrt{2}}{10000} \, \text{дм}^2$ .

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