QuestionRewrite $x^{2}+10 x+8$ as $(x+a)^{2}+b$ with integers $a$ and $b$.

Studdy Solution
Subtracting $b$ from our perfect square trinomial gives us our original equation$$(x+a)^{2} - b = (x+5)^{2} -17 = x^{2} +10x +8$$So, the given equation $x^{2}+10x+8$ can be written in the form $(x+a)^{2}+b$ as $(x+5)^{2}-17$.