QuestionSet A Set B -2 7 -4 9 0 -1 Answer Attempt 2 out of 2 The mapping diagram above \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ a function since \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ in \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ where there \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_.
Studdy Solution
The mapping diagram above is **not** a function since there is an element in Set A where there are multiple outputs in Set B.
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