Math  /  Calculus

QuestionSet up, but do not evaluate, an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. y=10xx2,y=x; about x=120()dx\begin{array}{r} y=10 x-x^{2}, y=x ; \text { about } x=12 \\ \int_{0}(\square) d x \end{array} Submit Answer

Studdy Solution
Substitute the expressions for the radius and height into the integral:
V=2π09(12x)(9xx2)dx V = 2\pi \int_{0}^{9} (12 - x)(9x - x^2) \, dx
The integral set up for the volume is:
V=2π09(12x)(9xx2)dx V = 2\pi \int_{0}^{9} (12 - x)(9x - x^2) \, dx

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