Math  /  Algebra

Question设函数 f(x)=ex(x0)f(x)=e^{x}(x \neq 0),求 f(x1)f(x2)f\left(x_{1}\right) \cdot f\left(x_{2}\right) 的结果。选项是:A. f(x1)+f(x2)f\left(x_{1}\right)+f\left(x_{2}\right) B. f(x1+x2)f\left(x_{1}+x_{2}\right) C. f(x1)f(x2)f\left(x_{1}\right)-f\left(x_{2}\right) D. f(x1x2)f\left(\frac{x_{1}}{x_{2}}\right)

Studdy Solution
Now, we can express ex1+x2e^{x_{1} + x_{2}} in terms of the function f(x)f(x).
f(x1)f(x2)=f(x1+x2)f\left(x_{1}\right) \cdot f\left(x_{2}\right) = f\left(x_{1} + x_{2}\right)So, the correct answer is B. f(x1+x2)f\left(x_{1}+x_{2}\right).

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