Math  /  Algebra

QuestionSimplify the expression: 15a124a2115a1+56a2\frac{1-5 a^{-1}-24 a^{-2}}{1-15 a^{-1}+56 a^{-2}}.

Studdy Solution
The term (a8)(a-8) appears in both the numerator and denominator, so we can cancel it out.
(a8)(a+3)(a8)(a7)=a+3a7\frac{(a-8)(a+3)}{(a-8)(a-7)} = \frac{a+3}{a-7}This is the simplified form of the expression, assuming a8a \neq8 and a7a \neq7 to avoid division by zero.

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