Question$\operatorname{Sin}^{2} \alpha \operatorname{Cos}^{2} \beta-\operatorname{Cos}^{2} \alpha \operatorname{Sin}^{2} \beta=\operatorname{Sin}^{2} \alpha-\operatorname{Sin}^{2} \beta$

Studdy Solution
Now compare the simplified left-hand side with the right-hand side of the original equation:
The right-hand side is:
$$\operatorname{Sin}^{2} \alpha - \operatorname{Sin}^{2} \beta$$
Both sides are equal, confirming the given identity.