Math  /  Trigonometry

Questionsin1(1.94)=\sin ^{-1}(1.94)= \square tan1(2.27)=\tan ^{-1}(2.27)= \square cos1(0.62)=\cos ^{-1}(-0.62)= \square

Studdy Solution
Evaluate cos1(0.62)\cos^{-1}(-0.62):
The value 0.62-0.62 is within the domain of the inverse cosine function, which is [1,1][-1, 1]. We can find cos1(0.62)\cos^{-1}(-0.62) using a calculator or table of values. The approximate value is:
cos1(0.62)2.24\cos^{-1}(-0.62) \approx 2.24 radians.
The solutions are:
sin1(1.94)=undefined\sin^{-1}(1.94) = \text{undefined}
tan1(2.27)1.15\tan^{-1}(2.27) \approx 1.15
cos1(0.62)2.24\cos^{-1}(-0.62) \approx 2.24

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