Math  /  Trigonometry

QuestionSolve for the general form of all solutions: 2cos(x)=12 \cos (x)=1 Give your answers as radian measures rounded to 4 decimal places. The "pattern" part of your answers should be kπk \pi or 2kπ2 k \pi. If you do not need both answer boxes, enter DNE instead of leaving one blank. x=x= \square or x=x= \square , where kZk \in \mathbb{Z}.

Studdy Solution
Since the cosine function is periodic with a period of 2π 2\pi , the general solutions can be expressed as:
x=π3+2kπ x = \frac{\pi}{3} + 2k\pi x=5π3+2kπ x = \frac{5\pi}{3} + 2k\pi
where kZ k \in \mathbb{Z} .
The general form of all solutions is:
x=π3+2kπ x = \frac{\pi}{3} + 2k\pi or x=5π3+2kπ x = \frac{5\pi}{3} + 2k\pi
where kZ k \in \mathbb{Z} .

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