QuestionSolve for x . $$\log _{8} x+\log _{8}(x-12)=2$$

Studdy Solution
Verify the solutions to ensure they satisfy the domain restrictions $x > 0$ and $x - 12 > 0$:
1. For $x = 16$: - $x > 0$ is satisfied. - $x - 12 = 4 > 0$ is satisfied.
2. For $x = -4$: - $x > 0$ is not satisfied.
Thus, the only valid solution is $x = 16$.
The value of $x$ is:
$$\boxed{16}$$