Math  /  Algebra

Question Solve 10x+y=x2+210x + y = -x^2 + 2 for real solutions. Determine if there are 0, 1, or 2 real solutions.

Studdy Solution
Since the discriminant Δ>0\Delta > 0, the quadratic equation has two distinct real solutions.
The equation 10x+y=x2+210x + y = -x^2 + 2 has two real solutions.

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