Math  /  Algebra

Question Solve the quadratic equation 2y(y+5)5=02y(y+5)-5=0 using the quadratic formula. Provide the solution(s) in the form y=y=\square.

Studdy Solution
We have two solutions for yy, one with the plus sign and one with the minus sign.
y1=5+352,y2=5352y_1 = \frac{-5 + \sqrt{35}}{2}, \quad y_2 = \frac{-5 - \sqrt{35}}{2}
The solutions to the equation 2y(y+5)5=02y(y+5)-5=0 are:
y=5+352,5352 y=\frac{-5 + \sqrt{35}}{2}, \frac{-5 - \sqrt{35}}{2}

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