Math  /  Algebra

QuestionFactor and solve the equation 4a2+11a20=04 a^{2}+11 a-20=0. Find values for aa:
a= a= or a= a=

Studdy Solution
olving the second equation a+4=0a +4 =0 for aa givesa=4a = -4So, the solutions to the equation 4a2+a20=04a^2 +a -20 =0 are a=5/4a =5/4 and a=4a = -4.

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