QuestionSolve the equation. (Enter your answers as a comma-separated list.) $\begin{array}{l} z^{2}+12 z+35=0 \\ z=1 \end{array}$

Studdy Solution
So, our solutions are $z = -5$ and $z = -7$ .
We write this as $-5, -7$ .
Notice how $z=1$ wasn't a solution after all!

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