Math  /  Trigonometry

QuestionSolve the equation on the interval [0,2π)[0,2 \pi). Give the exact solution in radians and give an approximation in degrees rounded to 1 decimal place. cosx=16\cos x=\frac{1}{6}
Part: 0 / 2
Part 1 of 2
The exact solution set in radians is \square \}.
Write your answer in simplest form.

Studdy Solution
To convert the solutions to degrees and provide an approximation, use the conversion factor 180/π180^\circ/\pi.
1. Approximate cos1(16) \cos^{-1}\left(\frac{1}{6}\right) in degrees:
cos1(16)80.4 \cos^{-1}\left(\frac{1}{6}\right) \approx 80.4^\circ
2. Approximate 2πcos1(16) 2\pi - \cos^{-1}\left(\frac{1}{6}\right) in degrees:
2πcos1(16)36080.4=279.6 2\pi - \cos^{-1}\left(\frac{1}{6}\right) \approx 360^\circ - 80.4^\circ = 279.6^\circ
The exact solution set in radians is:
{cos1(16),2πcos1(16)} \left\{ \cos^{-1}\left(\frac{1}{6}\right), 2\pi - \cos^{-1}\left(\frac{1}{6}\right) \right\}
The approximate solution set in degrees is:
{80.4,279.6} \left\{ 80.4^\circ, 279.6^\circ \right\}

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