QuestionSolve the equation using addition and multiplication principles:
$$5[7-5(6-r)]-7=7[5(7 r-6)+4]-50$$
What is the solution? A. $r=\square$, B. all real numbers, C. no solution.

Studdy Solution
To check our solution, we substitute r =1/2 back into the original equation and simplify to see if both sides of the equation are equal.
$$5[7-5(6-\frac{1}{2})]-7=7[5(7 \times \frac{1}{2}-6)+4]-50$$which simplifies to$$5[7-5 \times \frac{11}{2}]-7=7[5 \times \frac{7}{2}-30+4]-50$$which simplifies further to$$5[-\frac{3}{2}]-7=7[\frac{7}{2}-26]-50$$which simplifies to$$-\frac{15}{2}-7=-\frac{63}{2}-50$$which simplifies to$$-\frac{29}{2}=-\frac{113}{2}$$Since both sides of the equation are not equal, there is no solution for the given equation.
So the correct choice is C. There is no solution.