Math  /  Algebra

QuestionSolve the exponential equation 3e2xex=03 e^{2 x}-e^{x}=0

Studdy Solution
Since ln(13)=ln(1)ln(3)=0ln(3)=ln(3)\ln\left(\frac{1}{3}\right) = \ln(1) - \ln(3) = 0 - \ln(3) = -\ln(3), the solution is:
x=ln(3)x = -\ln(3)
The solution to the equation 3e2xex=03 e^{2x} - e^x = 0 is:
x=ln(3)x = -\ln(3)

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