QuestionSolve the following system of equations. $$\begin{array}{l} \frac{1}{6} x-\frac{1}{3} y=-4 \\ \frac{1}{4} x+\frac{3}{5} y=5 \end{array}$$ $$\begin{array}{l} x=\square \\ y=\square \end{array}$$

Studdy Solution
Verify the solution by substituting $x = -4$ and $y = 10$ into the second original equation:
$$\frac{1}{4}(-4) + \frac{3}{5}(10) = 5$$
Simplify:
$$-1 + 6 = 5$$
Both sides are equal, confirming the solution is correct.
The solution is:
$$\begin{array}{l} x = -4 \\ y = 10 \end{array}$$