Math  /  Algebra

QuestionSolve the following system of equations. x+8y=23x10y=27\begin{aligned} x+8 y & =23 \\ -x-10 y & =-27 \end{aligned} x=y=\begin{array}{l} x= \\ y= \end{array} \square \square

Studdy Solution
Verify the solution by substituting x=7 x = 7 and y=2 y = 2 back into the original equations:
First equation:
7+8(2)=237+16=2323=237 + 8(2) = 23 \quad \Rightarrow \quad 7 + 16 = 23 \quad \Rightarrow \quad 23 = 23
Second equation:
710(2)=27720=2727=27-7 - 10(2) = -27 \quad \Rightarrow \quad -7 - 20 = -27 \quad \Rightarrow \quad -27 = -27
Both equations are satisfied.
The solution is:
x=7,y=2\boxed{x = 7}, \quad \boxed{y = 2}

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