Math  /  Algebra

QuestionFactor the quadratic function f(x)=4x29f(x)=4x^{2}-9 and find the values for xx in x=[?]2;x=3[]x=-\frac{[?]}{2}; x=\frac{3}{[]}.

Studdy Solution
olving the second equation for x gives2x3=02x=3x=322x-3=0 \Rightarrow2x=3 \Rightarrow x=\frac{3}{2}So, the solutions are x=32x=-\frac{3}{2} and x=32x=\frac{3}{2}.
Therefore, the number that belongs in the green box for x=[?]2x=-\frac{[?]}{2} is3 and the number that belongs in the green box for x=3[]x=\frac{3}{[]} is2.

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