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QuestionSolve the system by the method of elimination and check any solutions algebraically. (If the real number a.) {0.2x−0.3y=3.20.7x+0.5y=5.0(x,y)=(□)\begin{array}{r} \left\{\begin{array}{l} 0.2 x-0.3 y=3.2 \\ 0.7 x+0.5 y=5.0 \end{array}\right. \\ (x, y)=(\square) \end{array} Need Help? Read It Watch It

Studdy Solution
Check the solution (x,y)=(10,−4)(x, y) = (10, -4) by substituting into the second original equation:
0.7(10)+0.5(−4)=5.00.7(10) + 0.5(-4) = 5.0
Simplify:
7−2=5.07 - 2 = 5.0
The solution satisfies both equations.
The solution to the system is:
(x,y)=(10,−4)(x, y) = (10, -4)

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